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16-6x^2=x^2
We move all terms to the left:
16-6x^2-(x^2)=0
We add all the numbers together, and all the variables
-7x^2+16=0
a = -7; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-7)·16
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{7}}{2*-7}=\frac{0-8\sqrt{7}}{-14} =-\frac{8\sqrt{7}}{-14} =-\frac{4\sqrt{7}}{-7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{7}}{2*-7}=\frac{0+8\sqrt{7}}{-14} =\frac{8\sqrt{7}}{-14} =\frac{4\sqrt{7}}{-7} $
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